x^2-2x+0,75=0

Solution for x^2-2x+0,75=0 equation:

x^2-2x+0.75=0

a = 1; b = -2; c = +0.75;
Δ = b2-4ac
Δ = -22-4·1·0.75
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-1}{2*1}=\frac{1}{2}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+1}{2*1}=\frac{3}{2}
=1+1/2
$